Optimal. Leaf size=253 \[ \frac {5 e^4 (a+b x) (b d-a e) \log (a+b x)}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {10 e^3 (b d-a e)^2}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e^2 (b d-a e)^3}{b^6 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e (b d-a e)^4}{3 b^6 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(b d-a e)^5}{4 b^6 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {e^5 x (a+b x)}{b^5 \sqrt {a^2+2 a b x+b^2 x^2}} \]
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Rubi [A] time = 0.18, antiderivative size = 253, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {646, 43} \begin {gather*} -\frac {10 e^3 (b d-a e)^2}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e^2 (b d-a e)^3}{b^6 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^4 (a+b x) (b d-a e) \log (a+b x)}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e (b d-a e)^4}{3 b^6 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(b d-a e)^5}{4 b^6 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {e^5 x (a+b x)}{b^5 \sqrt {a^2+2 a b x+b^2 x^2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 646
Rubi steps
\begin {align*} \int \frac {(d+e x)^5}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx &=\frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \frac {(d+e x)^5}{\left (a b+b^2 x\right )^5} \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\\ &=\frac {\left (b^4 \left (a b+b^2 x\right )\right ) \int \left (\frac {e^5}{b^{10}}+\frac {(b d-a e)^5}{b^{10} (a+b x)^5}+\frac {5 e (b d-a e)^4}{b^{10} (a+b x)^4}+\frac {10 e^2 (b d-a e)^3}{b^{10} (a+b x)^3}+\frac {10 e^3 (b d-a e)^2}{b^{10} (a+b x)^2}+\frac {5 e^4 (b d-a e)}{b^{10} (a+b x)}\right ) \, dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\\ &=-\frac {10 e^3 (b d-a e)^2}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(b d-a e)^5}{4 b^6 (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e (b d-a e)^4}{3 b^6 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {5 e^2 (b d-a e)^3}{b^6 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {e^5 x (a+b x)}{b^5 \sqrt {a^2+2 a b x+b^2 x^2}}+\frac {5 e^4 (b d-a e) (a+b x) \log (a+b x)}{b^6 \sqrt {a^2+2 a b x+b^2 x^2}}\\ \end {align*}
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Mathematica [A] time = 0.12, size = 242, normalized size = 0.96 \begin {gather*} \frac {-77 a^5 e^5+a^4 b e^4 (125 d-248 e x)-2 a^3 b^2 e^3 \left (15 d^2-220 d e x+126 e^2 x^2\right )-2 a^2 b^3 e^2 \left (5 d^3+60 d^2 e x-270 d e^2 x^2+24 e^3 x^3\right )+a b^4 e \left (-5 d^4-40 d^3 e x-180 d^2 e^2 x^2+240 d e^3 x^3+48 e^4 x^4\right )-60 e^4 (a+b x)^4 (a e-b d) \log (a+b x)-\left (b^5 \left (3 d^5+20 d^4 e x+60 d^3 e^2 x^2+120 d^2 e^3 x^3-12 e^5 x^5\right )\right )}{12 b^6 (a+b x)^3 \sqrt {(a+b x)^2}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [B] time = 9.44, size = 5910, normalized size = 23.36 \begin {gather*} \text {Result too large to show} \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 0.40, size = 412, normalized size = 1.63 \begin {gather*} \frac {12 \, b^{5} e^{5} x^{5} + 48 \, a b^{4} e^{5} x^{4} - 3 \, b^{5} d^{5} - 5 \, a b^{4} d^{4} e - 10 \, a^{2} b^{3} d^{3} e^{2} - 30 \, a^{3} b^{2} d^{2} e^{3} + 125 \, a^{4} b d e^{4} - 77 \, a^{5} e^{5} - 24 \, {\left (5 \, b^{5} d^{2} e^{3} - 10 \, a b^{4} d e^{4} + 2 \, a^{2} b^{3} e^{5}\right )} x^{3} - 12 \, {\left (5 \, b^{5} d^{3} e^{2} + 15 \, a b^{4} d^{2} e^{3} - 45 \, a^{2} b^{3} d e^{4} + 21 \, a^{3} b^{2} e^{5}\right )} x^{2} - 4 \, {\left (5 \, b^{5} d^{4} e + 10 \, a b^{4} d^{3} e^{2} + 30 \, a^{2} b^{3} d^{2} e^{3} - 110 \, a^{3} b^{2} d e^{4} + 62 \, a^{4} b e^{5}\right )} x + 60 \, {\left (a^{4} b d e^{4} - a^{5} e^{5} + {\left (b^{5} d e^{4} - a b^{4} e^{5}\right )} x^{4} + 4 \, {\left (a b^{4} d e^{4} - a^{2} b^{3} e^{5}\right )} x^{3} + 6 \, {\left (a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 4 \, {\left (a^{3} b^{2} d e^{4} - a^{4} b e^{5}\right )} x\right )} \log \left (b x + a\right )}{12 \, {\left (b^{10} x^{4} + 4 \, a b^{9} x^{3} + 6 \, a^{2} b^{8} x^{2} + 4 \, a^{3} b^{7} x + a^{4} b^{6}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \mathit {sage}_{0} x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.07, size = 449, normalized size = 1.77 \begin {gather*} -\frac {\left (60 a \,b^{4} e^{5} x^{4} \ln \left (b x +a \right )-60 b^{5} d \,e^{4} x^{4} \ln \left (b x +a \right )-12 b^{5} e^{5} x^{5}+240 a^{2} b^{3} e^{5} x^{3} \ln \left (b x +a \right )-240 a \,b^{4} d \,e^{4} x^{3} \ln \left (b x +a \right )-48 a \,b^{4} e^{5} x^{4}+360 a^{3} b^{2} e^{5} x^{2} \ln \left (b x +a \right )-360 a^{2} b^{3} d \,e^{4} x^{2} \ln \left (b x +a \right )+48 a^{2} b^{3} e^{5} x^{3}-240 a \,b^{4} d \,e^{4} x^{3}+120 b^{5} d^{2} e^{3} x^{3}+240 a^{4} b \,e^{5} x \ln \left (b x +a \right )-240 a^{3} b^{2} d \,e^{4} x \ln \left (b x +a \right )+252 a^{3} b^{2} e^{5} x^{2}-540 a^{2} b^{3} d \,e^{4} x^{2}+180 a \,b^{4} d^{2} e^{3} x^{2}+60 b^{5} d^{3} e^{2} x^{2}+60 a^{5} e^{5} \ln \left (b x +a \right )-60 a^{4} b d \,e^{4} \ln \left (b x +a \right )+248 a^{4} b \,e^{5} x -440 a^{3} b^{2} d \,e^{4} x +120 a^{2} b^{3} d^{2} e^{3} x +40 a \,b^{4} d^{3} e^{2} x +20 b^{5} d^{4} e x +77 a^{5} e^{5}-125 a^{4} b d \,e^{4}+30 a^{3} b^{2} d^{2} e^{3}+10 a^{2} b^{3} d^{3} e^{2}+5 a \,b^{4} d^{4} e +3 b^{5} d^{5}\right ) \left (b x +a \right )}{12 \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}} b^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.54, size = 443, normalized size = 1.75 \begin {gather*} \frac {1}{12} \, e^{5} {\left (\frac {12 \, b^{5} x^{5} + 48 \, a b^{4} x^{4} - 48 \, a^{2} b^{3} x^{3} - 252 \, a^{3} b^{2} x^{2} - 248 \, a^{4} b x - 77 \, a^{5}}{b^{10} x^{4} + 4 \, a b^{9} x^{3} + 6 \, a^{2} b^{8} x^{2} + 4 \, a^{3} b^{7} x + a^{4} b^{6}} - \frac {60 \, a \log \left (b x + a\right )}{b^{6}}\right )} + \frac {5}{12} \, d e^{4} {\left (\frac {48 \, a b^{3} x^{3} + 108 \, a^{2} b^{2} x^{2} + 88 \, a^{3} b x + 25 \, a^{4}}{b^{9} x^{4} + 4 \, a b^{8} x^{3} + 6 \, a^{2} b^{7} x^{2} + 4 \, a^{3} b^{6} x + a^{4} b^{5}} + \frac {12 \, \log \left (b x + a\right )}{b^{5}}\right )} - \frac {5}{6} \, d^{2} e^{3} {\left (\frac {12 \, x^{2}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{2}} + \frac {8 \, a^{2}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{4}} + \frac {6 \, a}{b^{6} {\left (x + \frac {a}{b}\right )}^{2}} - \frac {8 \, a^{2}}{b^{7} {\left (x + \frac {a}{b}\right )}^{3}} - \frac {3 \, a^{3}}{b^{8} {\left (x + \frac {a}{b}\right )}^{4}}\right )} - \frac {5}{12} \, d^{4} e {\left (\frac {4}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{2}} - \frac {3 \, a}{b^{6} {\left (x + \frac {a}{b}\right )}^{4}}\right )} - \frac {5}{6} \, d^{3} e^{2} {\left (\frac {6}{b^{5} {\left (x + \frac {a}{b}\right )}^{2}} - \frac {8 \, a}{b^{6} {\left (x + \frac {a}{b}\right )}^{3}} + \frac {3 \, a^{2}}{b^{7} {\left (x + \frac {a}{b}\right )}^{4}}\right )} - \frac {d^{5}}{4 \, b^{5} {\left (x + \frac {a}{b}\right )}^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (d+e\,x\right )}^5}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (d + e x\right )^{5}}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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